0=x^2-195x+8100

Solution for 0=x^2-195x+8100 equation:

0=x^2-195x+8100

We move all terms to the left:

0-(x^2-195x+8100)=0

We add all the numbers together, and all the variables

-(x^2-195x+8100)=0

We get rid of parentheses

-x^2+195x-8100=0

We add all the numbers together, and all the variables

-1x^2+195x-8100=0

a = -1; b = 195; c = -8100;
Δ = b2-4ac
Δ = 1952-4·(-1)·(-8100)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(195)-75}{2*-1}=\frac{-270}{-2}
=+135
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(195)+75}{2*-1}=\frac{-120}{-2}
=+60
$